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The reaction of 5.60 g of carbon with excess O2 yields 11.6 g of CO2. What is the percent yield of this reaction?

User Ken Smith
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Answer:

Step-by-step explanation:

To calculate the percent yield of the reaction, we need to compare the actual yield of the reaction (11.6 g of CO2) to the theoretical yield of the reaction, which we can calculate using stoichiometry.

The balanced equation for the reaction is:

C + O2 → CO2

From the equation, we can see that the mole ratio of carbon to carbon dioxide is 1:1. Therefore, the theoretical yield of CO2 can be calculated from the mass of carbon used in the reaction:

molar mass of carbon = 12.01 g/mol

moles of carbon = 5.60 g / 12.01 g/mol = 0.466 mol

moles of CO2 produced = 0.466 mol

mass of CO2 produced = moles of CO2 × molar mass of CO2

mass of CO2 produced = 0.466 mol × 44.01 g/mol = 20.5 g

So the theoretical yield of CO2 is 20.5 g.

Now we can calculate the percent yield of the reaction:

percent yield = (actual yield / theoretical yield) × 100%

percent yield = (11.6 g / 20.5 g) × 100%

percent yield = 56.6%

Therefore, the percent yield of the reaction is 56.6%.

User Patrick Kelly
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