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Systems of equations

4x-3y=1
2x+y=3

User Humanzz
by
6.9k points

1 Answer

2 votes

Answer:

x = 1

y = 1

Explanation:

Solving system of linear equations:

4x - 3y = 1 ---------------(I)

2x + y = 3 --------------(II)

Multiply equation (II) by (-2) and then add. 'x' will be eliminated, and we can find the value of 'y'.

(I) 4x - 3y = 1

(II)* (-2) -4x - 2y = -6 {Now, add}

-5y = -5

Divide both sides by (-5)

y = -5 ÷ (-5)


\sf \boxed{\bf y = 1}

Substitute y= 1 in equation (II) and find the value of 'x',

2x + 1 = 3

Subtract 1 from both sides,

2x = 3 - 1

2x = 2

Divide both sides by 2,

x = 2 ÷ 2


\sf \boxed{\bf x = 1}

User Harschware
by
7.4k points