Question

An arithmetic sequence begins with 25, 31, 37, 43, 49

Which option below represents the formula for the sequence?
f(n) = 25+ 6(n)
f(n)=25+6(n+1)
f(n)=25+6(n-1)
f(n)= 19 +6(n+1)

Answer 1

The formula for the given arithmetic sequence is f(n) = 25 + 6(n-1).

Step-by-step explanation:

The given arithmetic sequence begins with 25, 31, 37, 43, 49. To find the formula for the sequence, we need to determine the common difference. The common difference is the difference between any two consecutive terms in the sequence. In this case, the common difference is 31 - 25 = 6.

Since the first term is 25, we can use the formula f(n) = a + d(n-1), where a is the first term, d is the common difference, and n is the term position. Substituting the values, the correct formula for the sequence is f(n) = 25 + 6(n-1).