Question

What volume is occupied by 1.00 mole of an ideal gas at 2.00 atm and a temperature of 20.0°c?

Answer 1

Explanation: for ideal gas equation pv = nRT

p = pressure of the gas =2 atm

v = volume of gas=?

n=number of moles of ideal gas=1

T= temperature =20.0°c= 20+273=293 k (kelvin)

conversion of degree Celsius into kelvin

R = universal gas constant =8.314

v=nRT/p

v = 1x8.314x293/2 =1218 L