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Given f (x)= x^2-x+1 find f(x+3) =

User Wasim Aftab
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1 Answer

18 votes
18 votes

Answer:

f(x+3) = x² + 5x + 10

Explanation:

We are given the following function:

f(x) = x²-x+1;

We have to find f(x+3).

To do so, every value of x on the function f is replaced by x+3. So

f(x) = x²-x+1;

Replacing each x by x+3

f(x+3) = (x+3)²-(x+3)+1 = x²+6x+9-x-3+1 = x² + 5x + 10

f(x+3) = x² + 5x + 10

User Papirrin
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