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The impact of a collision at 60 mph is how many times greater than at 30 mph?

User JasonYun
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Answer:

four times as great

Step-by-step explanation:

If we use the simple physics equations: F=ma, and (Vf^2-V0^2)/2d

we can see that since the final velocity of a crash is 0, the equation becomes F=m(V^2/2d). Assuming that we have the same distance to stop, when you double the velocity, the impact force is increased by four.

User Maowtm
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