Question

What is the value of X-intercept of the function below? 3y=- 6/4 (x+4)+12

Answer 1

We are given the equation:

`3y=-(6)/(4)(x+4)+12`

We need to solve the equation for the x-intercept. We first need to simplify the given equation into slope-intercept form.

`\begin{gathered} (3y)/(3)=(-(6)/(4)(x+4)+12)/(3) \\ \\ y=-(1)/(2)x-2+4_{} \\ y=-(x-4)/(2) \end{gathered}`

Then, we will set y = 0 and solve for x to find the x-intercept.

`\begin{gathered} 0=-(x-4)/(2) \\ 0=-x-4 \\ 4=-x \\ -x=4 \\ x=-4 \end{gathered}`

Therefore, the x-intercept is located where y = 0. This means that our coordinate pair will be (-4, 0).