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How much water should be added to 20mL of 17% alcohol solution to reduce the concentration to 10%

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Answer:

Explanation:

Let's call the amount of water that needs to be added "x" mL.

Initially, there are 20 mL of a 17% alcohol solution. This means that there is:

0.17 x 20 = 3.4 mL of alcohol in the solution.

When x mL of water is added, the total volume of the solution will be 20 + x mL. At this point, we want the concentration of alcohol to be 10%. So we can set up the following equation:

3.4 mL / (20 mL + x mL) = 0.10

Simplifying this equation, we get:

3.4 mL = 0.10 (20 mL + x mL)

3.4 mL = 2 mL + 0.10x mL

1.4 mL = 0.10x mL

x = 14 mL

Therefore, 14 mL of water should be added to 20 mL of a 17% alcohol solution to reduce the concentration to 10%.

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