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F(x)=x^2-3x-10

g(x)=x+2
(f+g)(2)=
(f-g)(-1)=
(f-g)(-1)=
(f x g)(1)=
(f/g)(4)=

User Sevki
by
7.3k points

1 Answer

6 votes

Answer:

  • + : 4
  • - : -13
  • × : -18
  • ÷ : 3

Explanation:

Given the functions f(x) = x² -3x -10 and g(x) = x +2, you want the values of ...

  • (f+g)(2)
  • (f-g)(-1)
  • (f×g)(1)
  • (f/g)(4)

(f+g)(2)

Using the values from the attached table, we find ...

(f+g)(2) = f(2) +g(2) = 0 +4 = 4

(f-g)(-1)

(f-g)(-1) = f(-1) -g(-1) = -12 -1 = -13

(f×g)(1)

(f×g)(1) = f(1)×g(1) = (-6)×(3) = -18

(f/g)(4)

(f/g)(4) = f(4)/g(4) = 18/6 = 3

F(x)=x^2-3x-10 g(x)=x+2 (f+g)(2)= (f-g)(-1)= (f-g)(-1)= (f x g)(1)= (f/g)(4)=-example-1
User Deadtime
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7.7k points