Question

If 1.2 g of ammonium bicarbonate is treated with .75 grams of sodium chloride, 63.0075 grams sodium bicarbonate will be produced. In this reaction NaCI is limiting reagent. True or false

Answer 1

True

Step-by-step explanation:

Limiting reagent is the reactant that determines the progress of the reaction. It determines how much of the product is formed.

The equation for this reaction is;

NaCl (aq) + NH4HCO3 (aq) → NaHCO3 (aq) + NH4Cl (aq)

From the reaction, 1 mol of NaCl reacts with 1 mol of NH4HCO3 to produce 1 mol of NaHCO3

Converting to masses using; Mass = Number of moles * Molar mass

58.44g of NaCl reacts with 79.056g of NH4HCO3

If we were to sue the whole 1.2 g of NH4HCO3 we would require xg of NaCl

58.44 = 79.056

x = 1.2

x = 0.887g

The fact that 1.2g of NH4HCO3 requires 0.887g of NaCl (which is less than the available 0.75g) means that NaCl is the limiting reagent.