Answer:
6.31 x 10^22 atoms of tungsten, W, in 19.3 cm^3
Step-by-step explanation:
I assume that "w" is supposed to read W, the element tungsten. (a small case w could mean anything).
We need the identify of the material, w, since the number of atoms present depends on its molar mass. (grams/mole).
Tungsten, W, has a molar mass of 183.8 grams/mole.
The density of W is 19.3 grams/cm^3. Since we have excatly 1 cm^3, we will have 19.3 grams of tungsten. Convert that into moles of tungsten by dividing by it;s molar mass (the number of grams required for 1 mole of atoms/molecules).
(19.3g W)/(183.9 grams/mole W) = 0.105 moles W
1 mole = 6.02 x 10^23 particles (in this case atoms)
(0.105 moles W)*(6.02 x 10^23 atoms/mole) = 6.31 x 10^22 atoms of tungsten, W. This is for 1 cm^3 of W.