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Write an equation of the line with a slope of 3/5 containing the point (5,-5).

2 Answers

2 votes

Answer:


\displaystyle 3x - 5y = 40\:or\:y = (3)/(5)x - 8

Explanation:

Plug all the information into the Slope-Intercept formula:


\displaystyle y = ax + c

−5 = ⅗[5] + c; −8 = c

3


\displaystyle y = (3)/(5)x - 8

If you were to plug the result into the Standard formula, do this:

y = ⅗x - 8

- ⅗x - ⅗x

_________

−⅗x + y = −8 [NO fractions, so multiply by the denominatour to eradicate them]

−5[−⅗x + y = −8] >>
\displaystyle 3x - 5y = 40

Now, you could leave the equation as
\displaystyle -3x + 5y = -40, but some teachers would prefer you eradicate the negative from the fraction as well.

I am joyous to assist you at any time.

User Mechkov
by
7.8k points
5 votes

Answer:

y = 3/5x - 8

Explanation:

You can use another way but this is the way you were most likly taught.

y = mx + b

-5 = 3/5(5) + b

-8 = b

y = 3/5x - 8

User Bigjosh
by
8.2k points

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