Question

Assuming the earth is a uniform sphere of mass M and radius R, show that the acceleration of free fall at the earth's surface is given by g=GM/R^2​

Answer 1

Below

Step-by-step explanation:

We know that Fgravity = m1 a for mass m1 and 'a' is 'g'

and we also know that

Fgravity = G m1 M / r^2 so we can equate the two definitions

m1 a = G m1 M / r^2 where M = mass of earth

Now divide both sides of the equation by 'm1 '

a = G m/r62 Done . ( a is g )