Answer:
A 50J
Step-by-step explanation:
Bullet work by wooden block
Abdoul kasum
A bullet of mass 0.010 kg and speed of 100 m/s is brought to rest in a wooden block
after penetrating a distance of 0.10 m. The work done on the bullet by the block is
When the bullet penetrates the wooden block, it experiences a force in the opposite direction to its motion, causing it to slow down and eventually come to a stop. This force does work on the bullet, reducing its kinetic energy and transferring it to the wooden block as heat and sound.
The work done on the bullet by the block is equal to the change in the bullet's kinetic energy. The initial kinetic energy of the bullet is:
KEi = (1/2)mv^2
= (1/2)(0.010 kg)(100 m/s)^2
= 50 J
At the point where the bullet comes to rest, its kinetic energy is zero, so the change in kinetic energy is:
ΔKE = KEf - KEi
= 0 - 50 J
= -50 J
The negative sign indicates that the bullet has lost 50 J of kinetic energy. This energy has been transferred to the wooden block in the form of heat and sound.
Therefore, the work done on the bullet by the block is +50 J. The positive sign indicates that the work is done by the block on the bullet, which is consistent with the fact that the block exerts a force on the bullet in the opposite direction to its motion.