Question

Find the slope of a line perpendicular to the line whose equation is 6 � + � = 8 6x+y=8. Fully simplify your answer

Answer 1

perpendicular slope =
`(1)/(6)`

Explanation:

the equation of a line in slope- intercept form is

y = mx + c ( m is the slope and c the y- intercept )

given

6x + y = 8 ( subtract 6x from both sides )

y = - 6x + 8 ← in slope- intercept form

with slope m = - 6

given a line with slope m then the slope of a line perpendicular to it is

`m_(perpendicular)` = -
`(1)/(m)` = -
`(1)/(-6)` =
`(1)/(6)`