Question

(mol conversion)What is the mass of 52.3 L of Fe203Round your masses to whole numbers and give your answers with the correct number of sig figs and units.

Answer 1

To find the mass of 52.3 L of Fe₂O₃ we have to convert those L into moles, and then the moles into grams.

We know that 1 mol of an ideal gas (at STP) occupies 22.4 L. We can use that conversion to find the number of moles.

moles of Fe₂O₃ = 52.3 L * 1 mol/(22.4 L)

moles of Fe₂O₃ = 2.33 moles

Now we can convert those moles into grams using the molar mass of Fe₂O₃.

atomic mass of Fe = 55.85 amu

atomic mass of O = 16.00 amu

molar mass of Fe₂O₃ = 2 * 55.85 + 3 * 16.00

molar mass of Fe₂O₃ = 159.7 g/mol

mass of Fe₂O₃ = molar mass of Fe₂O₃ * moles of Fe₂O₃

mass of Fe₂O₃ = 159.7 g/mol * 2.33 moles

mass of Fe₂O₃ = 372 g

Answer: the mass of 52.3 L of Fe₂O₃ is 372 g.