Answer:
To determine whether the system of equations has one solution, no solution, or infinite solutions, we can solve the system by elimination or substitution. Here, we will use substitution:
We can rearrange the second equation to solve for z:
-6x = 30
x = -5
Substituting x = -5 into the first equation:
y = 2x + 10
y = 2(-5) + 10
y = 0
Thus, the solution to the system of equations is x = -5 and y = 0.
Therefore, the system has one solution.