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I need someone to explain how this is done

2x^3-16=0

User Siliconpi
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1 Answer

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Answer:

The solution to the given cubic equation is x = 2.

Explanation:

To solve the cubic equation 2x³ - 16 = 0, use algebraic operations to isolate x.

Add 16 to both sides of the equation:


\implies 2x^3-16+16=0+16


\implies 2x^3=16

Divide both sides of the equation by 2:


\implies (2x^3)/(2)=(16)/(2)


\implies x^3=8

Rewrite 8 as 2³ since 2 × 2 × 2 = 8:


\implies x^3=2^3

Take the cube root of both sides of the equation:


\implies \sqrt[3]{x^3}=\sqrt[3]{2^3}


\implies x=2

Therefore, the solution to the given cubic equation is x = 2.

User DraganescuValentin
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