Question

Find the line parallel to y = -x-2

that includes the point (-5, 10).
Enter the value that belongs in the green box.
y - 10 = [?](x-
Remember: y-y₁=m(x-x₁)

Answer 1

The equation of the line that passes through the point is y - 10 = -(x + 5)

How to determine the equation of the line that passes through the point

From the question, we have the following parameters that can be used in our computation:

(-5, 10)

Parallel to the line y = -x - 2

This gives

y = -x - 2

The slope of this line is -1

Parallel lines have equal slopes

So, we have

y - Y = m(x - X)

Substitute the known values into the equation

y - 10 = -1(x + 5)

Evaluate

y - 10 = -(x + 5)

Hence, the equation of the line is y - 10 = -(x + 5)

Answer 2

y - 10 = - (x + 5)

Explanation:

the equation of a line in slope- intercept form is

y = mx + c ( m is the slope and c the y- intercept )

y = - x - 2 ← is in slope intercept form

with slope m = - 1

• Parallel lines have equal slopes

the equation of a line in point- slope form is

y - y₁ = m(x - x₁ )

where m is the slope and (x₁, y₁ ) is a point on the line

here m = - 1 and (x₁, y₁ ) = (- 5, 10 ) , then

y - 10 = - 1(x - (- 5) ) , that is

y - 10 = - (x + 5)