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Find the exact value of cot[sin^(-1)(-8/9)]

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Answer: Let's start by drawing a right triangle with an angle whose sine is equal to -8/9.

We can use the Pythagorean theorem to find the length of the third side:

sin(theta) = opposite / hypotenuse

-8/9 = opposite / 1

opposite = -8/9

adjacent = sqrt(1^2 - (-8/9)^2) = 1/9 * sqrt(65)

So, we have a triangle with an opposite side of -8/9 and an adjacent side of 1/9 * sqrt(65), and a hypotenuse of 1.

Now, we can find the value of cot(theta) using the definition of cotangent:

cot(theta) = adjacent / opposite

= (1/9 * sqrt(65)) / (-8/9)

= -sqrt(65) / 8

Therefore, the exact value of cot[sin^(-1)(-8/9)] is -sqrt(65)/8.

Explanation:

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