Question

An air Craft is travelling along a runway at a velocity of 25mls it accelerates at a rate 0f 4m/s² for a distance of 750m before taking off Calculate the take off speed​

Answer 1

To calculate the take off speed of the aircraft, we can use the formula v² = u² + 2as, where v is the final velocity, u is the initial velocity, a is the acceleration, and s is the distance traveled.

Given:
u = 25 m/s
a = 4 m/s²
s = 750 m

Plugging these values into the formula, we get:

v² = 25² + 2(4)(750)
v² = 625 + 6000
v² = 6625

Taking the square root of both sides, we get:

v = √6625
v ≈ 81.4 m/s

Therefore, the take off speed of the aircraft is approximately 81.4 m/s.