Answer:
CH3(CH2)3COO- + H+
Step-by-step explanation:
The dissociation of valeric acid (CH3(CH2)3COOH) can be represented by the following equation:
CH3(CH2)3COOH ⇌ CH3(CH2)3COO- + H+
In this equation, valeric acid (CH3(CH2)3COOH) donates a hydrogen ion (H+) to water (H2O) to form a hydronium ion (H3O+), while the valerate ion (CH3(CH2)3COO-) is formed as a result of the loss of the hydrogen ion.
The dissociation of valeric acid can also be expressed using an equilibrium constant (Ka), which is a measure of the acidity of the acid. The expression for Ka for valeric acid is:
Ka = [CH3(CH2)3COO-][H+] / [CH3(CH2)3COOH]
In this expression, [CH3(CH2)3COO-] represents the concentration of the valerate ion, [H+] represents the concentration of the hydronium ion, and [CH3(CH2)3COOH] represents the concentration of valeric acid.
The value of Ka for valeric acid is approximately 1.5 x 10^-5 at room temperature (25°C).