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A woman paddling a canoe downstream with the river current travels 28 miles in 2 hours. On the return trip, she paddles the same distance upstream against the river current in 7 hours. Write and solve a system of two linear equations to determine the rate of the boat in calm water and the rate of the current, both in miles per hour.

calm water

User Alan Araya
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What the person said above me
User Maantje
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Answer:

Explanation:

Let's use the following variables:

Let b be the speed of the boat in calm water in miles per hour.

Let c be the speed of the current in miles per hour.

When the woman paddles downstream with the current, her speed is b + c miles per hour. When she paddles upstream against the current, her speed is b - c miles per hour. We can use the formula:

distance = rate × time

to write two equations based on the information given:

Downstream: 28 = (b + c) × 2

Upstream: 28 = (b - c) × 7

Simplifying these equations, we get:

2b + 2c = 28

7b - 7c = 28

We now have a system of two linear equations with two variables. We can solve for b and c using any method of solving systems of equations. For example, we can use elimination to eliminate one of the variables. Multiplying the first equation by 7 and the second equation by 2, we get:

14b + 14c = 196

14b - 14c = 56

Adding the two equations, we get:

28b = 252

b = 9

Substituting b = 9 into one of the original equations, we can solve for c:

2(9) + 2c = 28

2c = 10

c = 5

Therefore, the speed of the boat in calm water is 9 miles per hour, and the speed of the current is 5 miles per hour.

User Timv
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