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Given Z1=4-2i, Z2=2+3i. Evaluate Z1/Z2

User Danyolgiax
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Answer:

Z1/Z2 is (8/13) + (6/13)i.

Explanation:

To evaluate Z1/Z2, we need to divide the complex number Z1 by the complex number Z2.

To do this, we can use the formula for dividing complex numbers:

(Z1/Z2) = (Z1 * (conjugate of Z2)) / (Z2 * (conjugate of Z2))

where the conjugate of a complex number is obtained by changing the sign of the imaginary part.

Using this formula, we have:

Z1/Z2 = (4-2i) / (2+3i)

We multiply both the numerator and denominator by the conjugate of Z2, which is (2-3i), to eliminate the imaginary part from the denominator:

Z1/Z2 = (4-2i) / (2+3i) * (2-3i) / (2-3i)

Expanding the numerator and denominator, we get:

Z1/Z2 = [(42) + (43i) - (23i) - (29i^2)] / [(22) + (23i) - (3i2) - (3i3i)]

Simplifying the terms, we get:

Z1/Z2 = (8 + 6i) / (4 + 9)

Z1/Z2 = (8 + 6i) / 13

Therefore, Z1/Z2 is (8/13) + (6/13)i.

User Subtleseeker
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