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Sheri saves nickels and dimes in a coin purse for her daughter. The total value of the coins in the purse is $0.70. The number of nickels is two less than six times the number of dimes.

How many nickels and how many dimes are in the coin purse?

User Simonwo
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Answer:

Explanation:

Let's start by assigning variables to represent the unknowns in the problem. We can use "n" to represent the number of nickels and "d" to represent the number of dimes.

From the problem statement, we know that the total value of the coins in the purse is $0.70. We can write an equation to represent this information:

0.05n + 0.10d = 0.70

We also know that the number of nickels is two less than six times the number of dimes. We can write an equation to represent this information:

n = 6d - 2

Now we can substitute the expression for "n" into the first equation:

0.05(6d - 2) + 0.10d = 0.70

Simplifying the left side of the equation, we get:

0.30d - 0.10 + 0.10d = 0.70

Combining like terms, we get:

0.40d = 0.80

Dividing both sides by 0.40, we get:

d = 2

So there are 2 dimes in the coin purse. Now we can use the second equation to find the number of nickels:

n = 6d - 2 = 6(2) - 2 = 10

So there are 10 nickels in the coin purse.

Therefore, Sheri has 10 nickels and 2 dimes in the coin purse for her daughter.

User Michael Pralow
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