Answer:
Explanation:
Let's start by figuring out how many green beads Enya had before giving some away.
Let g be the number of green beads Enya had initially, and let b be the number of blue beads. Then we know:
g + b = 280 (the total number of beads)
After giving away 3/5 of the green beads and 20 blue beads, Enya had g' green beads and b' blue beads left. We can set up two more equations:
g' = 2/5 g (Enya gave away 3/5 of the green beads, so she has 2/5 left)
b' = b - 20 (Enya gave away 20 blue beads)
We also know that the ratio of blue beads to green beads left is 1:10, which means:
b' / g' = 1/10
Substituting the expressions for g', b', and b from the earlier equations, we get:
(b - 20) / (2/5 g) = 1/10
Simplifying this equation, we get:
b - 20 = g/4
Now we have two equations with two variables:
g + b = 280
b - 20 = g/4
We can solve for g in the second equation:
g = 4(b - 20)
Substituting this expression for g into the first equation, we get:
4(b - 20) + b = 280
Simplifying and solving for b, we get:
5b = 360
b = 72
So Enya had 72 blue beads initially. We can use this to find the initial number of green beads:
g + 72 = 280
g = 208
Enya had 208 green beads initially.
After giving away 20 blue beads and 3/5 of the green beads, she had:
g' = 2/5 * 208 = 83
b' = 72 - 20 = 52
So Enya had a total of 83 + 52 = 135 beads left in the end.