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Suppose Jessica places $4500 in an account that pays 6% interest compounded each year.

Assume that no withdrawals are made from the account.
Follow the instructions below. Do not do any rounding.
(a) Find the amount in the account at the end of 1 year.
$[]
(b) Find the amount in the account at the end of 2 years.
$0
X
S

1 Answer

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(a) To find the amount in the account at the end of 1 year, we use the formula:

A = P(1 + r)^n

where A is the amount in the account at the end of the year, P is the principal (the initial amount deposited), r is the interest rate as a decimal, and n is the number of times the interest is compounded in a year. In this case, P = $4500, r = 0.06 (since the interest rate is 6%), and n = 1 (since the interest is compounded once a year). So, we have:

A = $4500(1 + 0.06)^1

= $4500(1.06)

= $4770

Therefore, the amount in the account at the end of 1 year is $4770.

(b) To find the amount in the account at the end of 2 years, we again use the formula:

A = P(1 + r)^n

However, in this case, n = 2 (since the interest is compounded twice in 2 years). So, we have:

A = $4500(1 + 0.06)^2

= $4500(1.1236)

= $5061.20

Therefore, the amount in the account at the end of 2 years is $5061.20.

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