Ba(OH)2 has one barium (Ba) atom, two hydroxide (OH) groups, and one oxygen (O) atom. So, the total number of atoms in one molecule of Ba(OH)2 would be:
1 Ba atom + 2 O atoms + 2 H atoms = 5 atoms
To find the number of molecules of Ba(OH)2 from 4.81*10^25 total atoms, we can use the Avogadro's number which states that 1 mole of any substance contains 6.022 x 10^23 particles. So,
1 mole Ba(OH)2 = 5 x 6.022 x 10^23 molecules Ba(OH)2
To find the number of moles of Ba(OH)2, we can divide the total number of atoms by the number of atoms in one molecule:
4.81 x 10^25 atoms / 5 atoms/molecule = 9.62 x 10^24 molecules of Ba(OH)2
Therefore, 9.62 x 10^24 molecules of Ba(OH)2 would be made from 4.81*10^25 total atoms.