Answer: Let's call the speed of the jet in still air "s" and the speed of the wind "w".
When flying with a tailwind, the ground speed of the jet is the sum of its airspeed and the speed of the wind, so we have:
ground speed = airspeed + wind speed
1124/4 = s + w
Simplifying this equation, we get:
281 = s + w
Similarly, when flying into a headwind, the ground speed of the jet is the difference between its airspeed and the speed of the wind, so we have:
ground speed = airspeed - wind speed
956/4 = s - w
Simplifying this equation, we get:
239 = s - w
We can now solve these two equations simultaneously to find the values of "s" and "w". Adding the two equations gives:
281 + 239 = 2s
520 = 2s
s = 260
Substituting this value back into either of the equations gives:
281 = 260 + w
w = 21
Therefore, the speed of the jet in still air is 260 mph and the speed of the wind is 21 mph.
Explanation: