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Brandon has a cup of quarters and dimes with a total value of $5.55. The number of quarters is five less than three times the number of dimes. How many quarters and how many dimes does Brandon have?

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Answer:

Explanation:

Let's use variables to represent the unknown quantities in the problem.Let:

q be the number of quarters

d be the number of dimes

We can set up a system of two equations based on the given information:

Equation 1: The total value of the coins is $5.55:

0.25q + 0.10d = 5.55


Equation 2: The number of quarters is five less than three times the number of dimes:

q = 3d - 5

We can substitute the second equation into the first equation for q, since we now know that q = 3d - 5:0.25(3d - 5) + 0.10d = 5.55

Simplifying and solving for d:

0.75d - 1.25 + 0.10d = 5.550.85d = 6.80d = 8So Brandon has 8 dimes. To find the number of quarters, we can use Equation 2:

q = 3d - 5 = 3(8) - 5 = 19

Therefore, Brandon has 19 quarters and 8 dimes.

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