Answer: Let's call the price of an adult's ticket "A" and the price of a child's ticket "C". We can use this information to set up a system of equations to solve for A and C:
From the first piece of information, we know that:
3A + 4C = 132
From the second piece of information, we know that:
2A + 3C = 94
Now we can solve for A and C using any method of solving a system of equations. One possible method is to use elimination:
Multiply the second equation by 2:
4A + 6C = 188
Subtract the first equation from the second equation:
4A + 6C - 3A - 4C = 188 - 132
Simplify and solve for A:
A + 2C = 56
A = 56 - 2C
Substitute this expression for A into either of the original equations:
3(56 - 2C) + 4C = 132
Simplify and solve for C:
C = 10
Substitute this value for C into the expression we found for A:
A = 56 - 2(10) = 36
Therefore, the price of an adult's ticket is $36, and the price of a child's ticket is $10.
Explanation: