Answer:
Step-by-step explanation:
The balanced chemical equation for the reaction between FeCl and Cl2 is:
2FeCl + Cl2 → 2FeCl3
From the equation, we can see that 1 mole of Cl2 reacts with 2 moles of FeCl. To find the amount of FeCl that reacted when 175.98 grams of Cl2 reacted, we need to follow a few steps:
Calculate the number of moles of Cl2 that reacted:
mass of Cl2 / molar mass of Cl2 = 175.98 g / 70.906 g/mol = 2.479 mol Cl2
Use the mole ratio from the balanced equation to find the number of moles of FeCl that reacted:
2 moles FeCl / 1 mole Cl2 = x moles FeCl / 2.479 moles Cl2
x moles FeCl = 2 moles FeCl / 1 mole Cl2 x 2.479 moles Cl2 = 4.958 moles FeCl
Calculate the mass of FeCl that reacted:
mass of FeCl = moles of FeCl x molar mass of FeCl = 4.958 moles x (55.845 + 35.453) g/mol = 340.3 g
Therefore, 340.3 grams of FeCl reacted when 175.98 grams of Cl2 reacted.