Question

A pizza pan is removed at 9 : 00 PM from an oven whose temperature is fixed at 425 degrees Upper F    into a room that is a constant 74 degrees F.    After 5​ minutes, the pizza pan is at 300 degrees F. ​(a) At what time is the temperature of the pan 135 degrees F question mark ​(b) Determine the time that needs to elapse before the pan is 200 degrees. ​(c) What do you notice about the temperature as time​ passes?

Answer 1

Answer: 9:11:48 p.m

9.8 minutes

Explanation:

We Obtian the slope of the relation :

Slope = Rise / Run

(0, 425) ; (5, 300)

x2 = 0 ; y2 = 425 ; x1 = 5 ; y1 = 300

(425 - 300) / (0 - 5)

125 / - 5

= - 25

The intercept :

y = mx + c

425 = - 25(0) + c

425 = 0 + c

c = 425

The equation becomes :

y = - 25x + 425

Temperature at 130

130 = - 25x + 425

130 - 425 = - 25x

-295 = - 25x

x = 11.8

9:00 + 11.8 = 9:11:48 p.m

B.)

180 = - 25x + 425

180 - 425 = - 25x

-245 = - 25x

x = 9.8 minutes