Question

En una palanca se aplicó una fuerza de 2 kg mas (19.6 N) cuyo brazo de fuerza es de 2.5 m, si la resistencia que se vence es de 40 kg mas (392 N), ¿cuál será la medida de su brazo de resistencia (d)?

Answer 1

the length of the resistance arm is 0.125 m.

Explanation:

To solve this problem, we can use the lever law, which states that the force applied on one arm of the lever is equal to the resistance overcome on the other arm of the lever. In this case, we can write:

Applied force * force arm = Resistance overcome * resistance arm

Substituting the known values:

(19.6 N) * (2.5 m) = (392 N) * d

Solving for d:

d = (19.6 N * 2.5 m) / (392 N)

d = 0.125 m

Therefore, the length of the resistance arm is 0.125 m.