Question

21. How many 2 1/2 cans of pork and beans are required to serve 95 people if each can weighs 1 lbs. 10 oz. and each serving size is 6 ounces

Answer 1

Step 1

Convert 10 oz to pounds

`10\text{ oz = }0.625\text{ pounds}`

Step 2

Find the total weight of a can of pork and beans in pounds

`1\text{ + 0.625 = 1.625lbs}`

Step 3

Convert the weight of 1 can in pounds to ounces

`1.625\text{lbs = }26\text{ ounces}`

Step 4

Find the weight of 5/2 cans of pork and beans.

`\begin{gathered} (1)/((5)/(2))=(26)/(x) \\ x=\text{ 26}*(5)/(2) \\ x=\text{ 65 ounces} \end{gathered}`

Step 5

Find the total weight of servings

`\begin{gathered} \frac{1\text{ serving}}{95\text{ servings}}=\frac{6\text{ ounces}}{y} \\ y\text{ = 95 }*6 \\ y\text{ = 570 ounces} \end{gathered}`

Step 6

Find how many 5/2 cans of pork needed for 95 people.

`\begin{gathered} =\frac{570\text{ ounces}}{65\text{ ounces}}=\text{ }(114)/(13)\text{ 2}(1)/(2)\text{ cans} \\ \approx8.769\text{ 2}(1)/(2)cans \end{gathered}`