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Ellis has a 30 oz. glass that is full (to the top) with a mixture of 40% cranberry juice

and 60% seltzer, and wants to change those percentages by spilling out some of the mixture
and topping off the glass with seltzer. How much of the original mixture should be drained
and then replaced with seltzer in order to end up with a 30 oz. mixture that is 20% cranberry
juice?

User NigelDcruz
by
6.8k points

2 Answers

3 votes

Answer:

Below

Explanation:

The Answer Will Be 6 Percent.

User Anton Shchastnyi
by
6.9k points
4 votes

Let's start by finding out how much cranberry juice is currently in the 30 oz. mixture. If the mixture is 40% cranberry juice, then the amount of cranberry juice in ounces is:

0.4 x 30 = 12 oz.

We want to end up with a 30 oz. mixture that is 20% cranberry juice. So the amount of cranberry juice in ounces we need in the new mixture is:

0.2 x 30 = 6 oz.

To achieve this, we need to remove some of the original mixture, which contains 12 oz. of cranberry juice, and replace it with seltzer, which contains 0 oz. of cranberry juice. Let's say we remove x oz. of the original mixture.

The amount of cranberry juice left in the mixture after we remove x oz. is:

12 - x

The amount of seltzer left in the mixture after we remove x oz. is:

30 - x

If we replace the x oz. of mixture we removed with seltzer, the amount of cranberry juice in the new mixture is:

12 - x + 0 = 12 - x

And the amount of seltzer in the new mixture is:

30 - x + x = 30

We want the new mixture to contain 6 oz. of cranberry juice, which is 20% of the total 30 oz. So we can set up an equation:

(12 - x) / 30 = 0.2

Simplifying this equation, we get:

12 - x = 6

x = 6

So we need to remove 6 oz. of the original mixture and replace it with 6 oz. of seltzer to end up with a 30 oz. mixture that is 20% cranberry juice.

User Benares
by
6.9k points