Question

Calculate the measure of the force received by the BAG conductor from the homogeneous magnetic field of intensity B = 0.2T

Answer 1

The expression for the magnetic force on a current lines is given by:

`F=\text{ilBsin}\theta`

where,

i: current = 10 A

B: magnitude of the magnetic field = 0.2T

l: length of the line

θ: angle between direction of the line and the magnetic field = 90 degrees.

You can notice that the direction of the magnetic field and direction of the conduction are perpendicular, then, you have for F:

`F=i\cdot l\cdot B\sin 90=i\cdot l\cdot B`

For the segment BA you obtain:

`F_(BA)=(10A)(0.08m)(0.2T)=0.16N`

and for segment AG:

`F_(AG)=(10A)(0.06m)(0.2T)=0.12T`

If you consider that segment BA lies on the y axis of a coordinate system and segment AG lies on x-axis (in this case BA and AG form a right angle), then, the total force on BAG is:

`\vec{F}=0.12T\hat{i}+0.16T\hat{j}`

and its magnitude is:

`F=\sqrt[]{(0.12T)^2+(0.16T)^2}=0.2N`