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Please help me with this problem I have been doing this on my own and every time I end up short it’s confusing help please immediately.

Please help me with this problem I have been doing this on my own and every time I-example-1

2 Answers

2 votes

Answer:

11 for booster

41 for premade

Explanation:

Let:

X = Booster packs

Y = Premade decks

Making a system of equations

3x + 10y = 443

x + 5y = 216

We can use the substitution method on the second method.

Subtracting 5y we get

x = 216 - 5y

Now that we have X, we can plug that into the first equation.

3(216-5y) +10y = 443

Distributing we get 648 - 15y + 10y = 443.

648 - 5y = 443.

If we subtract 648, we get -5y = -205

Dividing by -5 gets us to y = 41

Since Y was premade decks, that means each premade has 41 cards

Now we take that answer and plug it into the original equation of x + 5y = 216

x + 5(41) = 216

x + 205 = 216

x = 11

User Snap
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7.8k points
2 votes
Each booster pack has 11 cards, each pre made deck has 41 cards.

I wrote out my steps in the picture, but basically you can first create two equations, one with the cards he bought with his allowance money, and the other one with the cards he got for his birthday.

Then, solve for one of the variables and then use that to solve for the other.

If you have questions about any of the steps just let me know :)
Please help me with this problem I have been doing this on my own and every time I-example-1
User Aleksei Shestakov
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7.9k points