Answer:
12
Explanation:
Given T2=T4=0 and the second difference is 12, we can find the value of the common difference (d) as follows:
T4 = T2 + 2d
0 = 0 + 2d
d = 0
Now that we know the common difference is 0, we can use this to find the value of the first term (T1) as:
T1 = T2 - d = 0 - 0 = 0
We can then use the second difference to find the value of the second term (T2) as:
T3 - 2T2 + T1 = 12
T3 - 0 + 0 = 12
T3 = 12
Therefore, the 3rd term is 12.