Answer:
approximately 77,794 kg/m^3.
Explanation:
The volume of the metal bar can be calculated using the formula for the volume of a cylinder:
V = πr^2h
where r is the radius of the cylinder (which is half of the diameter), and h is the height of the cylinder (which is the length of the bar).
In this case, the radius is 6 cm / 2 = 3 cm = 0.03 m, and the height is 1 m. Therefore, the volume of the metal bar is:
V = π(0.03)^2(1) = 0.00028274334 m^3
The density of the metal can be calculated using the formula:
density = mass / volume
In this case, the mass is 22 kg, so:
density = 22 kg / 0.00028274334 m^3 ≈ 77,794 kg/m^3
Therefore, the density of the metal from which the bar is made is approximately 77,794 kg/m^3.