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A metal bar, 1m long and and with a diameter of 6 cm, has a mass of 22 kg. What is the density of the metal from which the bar is made

User Ntcong
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Answer:

approximately 77,794 kg/m^3.

Explanation:

The volume of the metal bar can be calculated using the formula for the volume of a cylinder:

V = πr^2h

where r is the radius of the cylinder (which is half of the diameter), and h is the height of the cylinder (which is the length of the bar).

In this case, the radius is 6 cm / 2 = 3 cm = 0.03 m, and the height is 1 m. Therefore, the volume of the metal bar is:

V = π(0.03)^2(1) = 0.00028274334 m^3

The density of the metal can be calculated using the formula:

density = mass / volume

In this case, the mass is 22 kg, so:

density = 22 kg / 0.00028274334 m^3 ≈ 77,794 kg/m^3

Therefore, the density of the metal from which the bar is made is approximately 77,794 kg/m^3.

User Hackworth
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