Question

Find the quotient Negative 9h with an exponent of 4 plus 27h with an exponent of 3 over h with an exponent of 2

Answer 1

`-9h^2+27h`

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Simplify by distributing, then dividing:

`\cfrac{-9h^4+27h^3}{h^2} =-\cfrac{9h^4}{h^2} +\cfrac{27h^3}{h^2} =-9h^(4-2)+27h^(3-2)=-9h^2+27h`