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If y varies directly as x and y is 48, when x is 6, which expression can be used to find the value of y when x is 2?

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If y varies directly as x, this means that y is directly proportional to x, or in other words, y = kx, where k is a constant of proportionality.

To find the value of k, we can use the information given in the problem: when x is 6, y is 48. Substituting these values into the equation, we get:

48 = k * 6

Solving for k, we get:

k = 8

Now that we know the value of k, we can use the equation y = kx to find the value of y when x is 2:

y = 8 * 2 = 16

Therefore, the expression that can be used to find the value of y when x is 2 is y = 8x, which gives y = 16 when x is 2.

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