Question

The line contains the point (3, 5) and is parallel to the line containing (-4, 0) and (-1, -2)

Answer 1

I Believe This is the answer

Answer: The line through (-4, -6, 1) and (-2, 0, -3), is parallel to the line through (10, 18, 4) and (5, 3, 14).

Explanation:

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Answer 2

To find the equation of the line passing through (3, 5) and parallel to the line containing (-4, 0) and (-1, -2), we need to use the slope-intercept form of a line:

y = mx + b

where m is the slope of the line and b is the y-intercept.

First, we need to find the slope of the line containing (-4, 0) and (-1, -2):

m = (y2 - y1) / (x2 - x1)

m = (-2 - 0) / (-1 - (-4))

m = -2 / 3

Since the line we're looking for is parallel to this line, it will have the same slope.

Now we can use the point-slope form of a line to find the equation of the line passing through (3, 5) with slope -2/3:

y - y1 = m(x - x1)

y - 5 = (-2/3)(x - 3)

Simplifying and rearranging, we get:

y = (-2/3)x + 7

So the equation of the line containing the point (3, 5) and parallel to the line containing (-4, 0) and (-1, -2) is y = (-2/3)x + 7.