To find the equation of the line passing through (3, 5) and parallel to the line containing (-4, 0) and (-1, -2), we need to use the slope-intercept form of a line:
y = mx + b
where m is the slope of the line and b is the y-intercept.
First, we need to find the slope of the line containing (-4, 0) and (-1, -2):
m = (y2 - y1) / (x2 - x1)
m = (-2 - 0) / (-1 - (-4))
m = -2 / 3
Since the line we're looking for is parallel to this line, it will have the same slope.
Now we can use the point-slope form of a line to find the equation of the line passing through (3, 5) with slope -2/3:
y - y1 = m(x - x1)
y - 5 = (-2/3)(x - 3)
Simplifying and rearranging, we get:
y = (-2/3)x + 7
So the equation of the line containing the point (3, 5) and parallel to the line containing (-4, 0) and (-1, -2) is y = (-2/3)x + 7.