Explanation:
first Pythagoras with the right, smaller right-angled triangle. that gives us the height of the total triangle, and the shorter leg of the left, larger right-angled triangle.
c² = a² + b²
c being the Hypotenuse (the side opposite of the 90° angle), a and b are the legs.
6² = 3.5² + height²
36 = 12.25 + height²
height² = 23.75
height = sqrt(23.75) = 4.873397172... cm
now, as mentioned, this height is also the second leg of the left, larger right-angled triangle.
and with a given angle, now trigonometry has to be used.
remember, what sine and cosine are ?
sine of an angle is the vertical (up/down) leg, and cosine is the horizontal (left/right) leg of the right-angled triangle created by the angle and inscribed in the (norm-)circle.
"norm-circle", because the radius is 1.
now, for a larger circumscribing circle (like in our case here), we need to multiply the actual radius by sine and cosine (and all other trigonometric functions).
the radius is the large, top-left side coming from the 30° angle.
we don't know the length yet, but we know the value of sin(30) multiplied by that length, which is the height we just calculated.
so,
sqrt(23.75) = sin(30)×radius
radius = sqrt(23.75)/sin(30)
sin(30) = 0.5 = 1/2
so,
radius = sqrt(23.75)/ 1/2 = sqrt(23.75)×2
x is now the cosine of the angle multiplied by the radius.
x = cos(30)×sqrt(23.75)×2 = 8.440971508... cm
≈ 8.4 cm