Question

A fruit punch that contains 60% fruit juice is combined with 100% fruit juice. How many ounces of each should be used to make 52 oz of a mixture that is 90%

fruit juice?

Answer 1

x = ounces of 10%

40 - x = ounces of 100%

(10%)x + (100%)(40 - x) = (55%)(40 oz)

10x + 100(40 - x) = 2200

-90x = -1800

x = 1800/90 = 20 oz

40 - x = 40 - 20 = 20 oz

You can solve this by setting up a weighted combination of the juices

Answer 2

A fruit punch that contains 25% fruit juice is combined with a fruit drink that contains 10% fruit juice? How many ounces of each should be used to make a 48oz of a mixture that is 15% fruit juice

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25% juice DATA:

Let x be amount of 25% juice: amt. of active ingredient = 0.25x ounces

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10% juice DATA:

Amt of 10% juice is "48-x" ; amt of active is 0.10(48-x)=4.8-0.1x ounces

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15% mixture DATA:

Amt = 48 ounces ; amt of active is 0.15(48) = 7.2 ounces

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EQUATION:

active + active = 7.2 ounces

0.25x + 4.8-0.1x = 7.2

0.15x = 2.4

x = 16 ounces ( amt of 25% juice that must be added)

48-x = 32 ounces (amt of 10% juice that must be added)

By 999JuiceWrld :)