Answer:
Ahmed is right in disagreeing with his friend
Explanation:
We can easily determine that Ahmed's friend is wrong by looking at the fraction a/b which has to be less than 1 since the distance from A toschool is less than the distance from A to B
Therefore b/a will be greater than 1 and hence b/a x length of BA will be greater than the distance from B to A which means the school cannot be located on the segment BA
An example will make this easier to understand
Let the segment AB be 12 units
Let a/b = 1/3
School is located 1/3 x AB length
b/a is reciprocal of 1/3 = 3
Friend suggests that school is b/a times distance BA
But b/a distance BA = 3BA which means the school is outside the segment BA
The correct answer is
The school is located (1 - a/b) the distance along BA