Answer:
the temperature rise when 25kg of the substance is heated with the same amount of heat is 2.2°C.
Step-by-step explanation:
The specific heat capacity of a substance is the amount of heat required to raise the temperature of one unit of mass of the substance by one degree Celsius.
Let's call the specific heat capacity of the substance "c", and the temperature rise we're trying to calculate "ΔT".
We can use the following formula to solve the problem:
Q = mcΔT
where Q is the amount of heat supplied to the substance, m is the mass of the substance, and c is the specific heat capacity of the substance.
Since the amount of heat supplied to the substance is the same in both cases, we can set the two expressions for Q equal to each other:
mcΔT = mc'ΔT'
where c' is the specific heat capacity of the substance when 25kg is heated, and ΔT' is the temperature rise we're trying to find.
We know that the mass of the substance has increased from 10kg to 25kg, so we can write:
cΔT = c'ΔT'
We can rearrange this equation to solve for ΔT':
ΔT' = (cΔT) / c'
Substituting the values we know into this equation, we get:
ΔT' = (c x 55°C) / (25kg x c)
We can simplify this expression by canceling out the "c" terms:
ΔT' = (55°C) / (25kg)
Evaluating this expression, we get:
ΔT' = 2.2°C
Therefore, the temperature rise when 25kg of the substance is heated with the same amount of heat is 2.2°C.