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A body of mass 12kg traveling at 4.2m/s collides with a second body of mass 18kg at rest. Calculate their common velocity if the bodies coalesce after collision

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La respondería si supiera inglés, pero es que no entiendo nada…
User Dinkar Thakur
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Answer:

.

The common velocity of the two bodies after the collision is 2.7 m/s.

This can be calculated using the equation of conservation of momentum:

m1v1 + m2v2 = (m1 + m2)v

where m1 is the mass of the first body (12 kg), v1 is the velocity of the first body (4.2 m/s), m2 is the mass of the second body (18 kg), v2 is the velocity of the second body (0 m/s), and v is the common velocity of the two bodies after the collision.

Substituting the given values into the equation, we get:

12(4.2) + 18(0) = (12 + 18)v

Solving for v, we get:

v = 2.7 m/s

User Bluebinary
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