Answer:
Explanation:
The statement is true. Here's an explanation:
If X represents a random variable coming from a normal distribution, we can use the properties of the standard normal distribution to find probabilities. The standard normal distribution has a mean of 0 and a standard deviation of 1.
We can convert any normal distribution to the standard normal distribution using the formula:
z = (x - μ) / σ
where x is a value from the normal distribution, μ is the mean of the normal distribution, σ is the standard deviation of the normal distribution, and z is the corresponding value on the standard normal distribution.
In this case, we know that P(X < 7.8) = 0.55. We can convert this to the standard normal distribution by subtracting the mean and dividing by the standard deviation:
P((X - μ) / σ < (7.8 - μ) / σ) = 0.55
We can use a standard normal distribution table (or calculator) to find the corresponding z-score for the probability 0.55. The closest value we can find in the table is 0.54, which corresponds to a z-score of 0.13.
So we have:
P(Z < 0.13) = 0.55
Now we can use the properties of the standard normal distribution to find P(Z > 0.13). Since the total area under the standard normal distribution curve is 1, we know that:
P(Z < 0.13) + P(Z > 0.13) = 1
Therefore:
P(Z > 0.13) = 1 - P(Z < 0.13) = 1 - 0.55 = 0.45
Since X and Z are related by the formula z = (x - μ) / σ, we can conclude that:
P(X > 7.8) = P((X - μ) / σ > (7.8 - μ) / σ) = P(Z > 0.13) = 0.45
Therefore, the statement "P(X > 7.8) = 0.45" is true.