Question

A 37.3 kg crate slides down a ramp. The ramp is 3.20 m long and is at a 37.0° angle. The crate starts from rest. It experiences a constant frictional force of 12.0 N as it slides downwards. What is the speed of the crate when it reaches the bottom?​

Answer 1

The speed of the crate when it reaches the bottom can be calculated using the equation:

v = √(2gh)

Where v is the speed, g is the acceleration due to gravity (9.8 m/s2), h is the height of the ramp (3.20 m).

Therefore, the speed of the crate is:

v = √(2 * 9.8 * 3.20) = 7.7 m/s